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Lorentz
and AD Transformations This article collects in one place several topics related to the Lorentz and Autodynamic (AD) transformations.
The argument that the transformation
needs to be linear and that successive transformations need to be invariant
applies to AD, of course. That
is, in going from T1 to T2 and from this to T3, T3 must be equal to
T1. However, the equations that
satisfy that transformation in Lorentz drive SR to a contradiction because
TWO observers will see different values according to each one's state
of motion.
If Lorentz’s transform from T1 to T3 forms a “group," it also forms a “group” in AD, even though in AD the concept is physically irrelevant, because the concept of groups is only a mathematical concept unrelated to any physical phenomenon.
The transformation needs to be linear, but we need to know what should be transformed from the physical point of view, not from a blind mathematical transformation. Though there are many ways
to effect the transformation using Algebra, Calculus, or Determinants
we will use Algebra since it is the simplest.
The Lorentz Transformation.
Fig 1.
If the light source is at the origin of the frame O (O for Observer) and a spherical electromagnetic wave is emitted at t = 0, the wave front will be at a distance ct (Point P) from the origin at time t. The distance to Point P is
or
If O’ is the moving reference frame, it will see the same wave front at P at a distance c t’ at time t’ and the equation is
The transformation will be invariant if replacing x’ y’ z’ and t’ as function of x,y,z and t in equation (4) the two equations (2) and (4) give an equal value.
That is:
0 = 0 To find the equations Lorentz used:
x’ = a x - b t (6)
t’ = e x - f t (7)
a, b, e, f [2] are values to be found.
If O’ is in motion with respect to O, Lorentz’s distance is
x’ = x - v t (8)
. Equation (6) is rearranged to
x’ = g (x - v t) (9)
The function of t is v t because x is a distance and v t is another distance to be added or subtracted to x.
Here
is the problem. Independent of the velocity that O’ has with respect
to O, x is a constant distance to O and will stay constant independent
of the O’ velocity with respect to O. Contrarily, if x is affected by
a value that will be function of a variable velocity v, as really happens
with the Lorentz’s coefficient As the values a, b, e, f need to be determined in equation (6) and (7), there is a possibility that a could be equal to ONE, but looking at equation (9) shows that a = b = g and, as g is not ONE, consequently a ¹ 1. Precisely as in the Lorentz equation (12)
a = b = g = 1 / root (1 – b^2) = g (10)
We can see this clearly, because equation (9) can be written as:
x’ = g x - g v t (11)
The very well known Lorentz equations are: (See Footnote 5)
These equations must satisfy the Lorentz transformation given by equation (5). If in equation (5), setting y’ = y and z’ = z, x’ and t’ is replaced by its values in equation (12) and (13) we have
Simplifying and multiplying by (1 - b2)
This mathematically correct solution involves physically wrong results given by equations (12) and (13), as we will show using very simple examples. Setting these values (using exactly the same example as in Feynman’s paper “Superfluous System” in the SAA’s Home Page):
x = 100 m t = 10-7 s v = 0.8 c c = 3 10-8 m
Applying equation (12) and (13) we have
These two results don’t make sense. The first, in equation (18) shows that O’ traveling to the point P's direction is far away from it and the time of travel is negative.
Distance x inserted in equation (6) or (9) or (11) or (12) will automatically increment its value because the root also divides x, this being erroneous because Point P is supposed to be “at rest.” The same happens with t. We need to point out here that v is not the phenomenon (P) velocity with respect to the Observer O’. v is the constant velocity between System O’ in relative motion with respect to O (See Fig. 1). Nevertheless, the velocity v, used in all the SR equations, is the velocity between Observer and Phenomenon and in this case the System O’ is not necessary. The contradiction is evident because in SR the phenomenon velocity will result from the x variation. (Phenomenon position through a mathematical differential that gives vx (equation (1.13) on page 16 on the AD’s book)) even though x is a constant distance. We will see that in AD everything makes sense.
AD’s TransformationUsing Fig. 1, AD’s reasoning is exactly the same as using Fig. 2. (See footnote 3)
Fig. 2.
When Carezani found the physical contradiction in Lorentz’s transform, he simultaneously discovered that to achieve relativity, it is not necessary to “introduce” two systems of coordinates to observe a phenomenon, even though he respected the Lorentz mathematical transformation for ONE Observer (O’) that sees the object's (wave front) motion from position X to X’(Fig 2). As will be shown later, this is not a unique solution, because the same will happen when “two systems” are involved. (See further “Two” frames in AD). [In Fig. 2 the Observer “at rest” is O’] The electromagnetic wave starts from the frame origin of O’. Distance x is the distance from the Origin of the System of Coordinates, x = y = z = 0 to point X, which is given by c t, or x = c t, written in the classic notation is:
x2 – c2
t2 = 0 (20)
When the electromagnetic wave front moves to point X’ (y’’), the distance is given by x’ = c t’ to Observer O’ and
x’2 – c2 t’2 = 0 (21)
The transformation needs to be invariant, that is
x2 – c2 t2 = x’2 – c2 t’2 (22)
That is 0 = 0
This equation (22) is exactly the same as equation (5) after setting y’ = y and z’ = z. Remembering that the velocity c is constant and independent of the Observer or Phenomenon velocity, t’ is the time that Observer O’ measures at the origin of his coordinate system. [In AD, only one system is needed to build a relativity theory.]
“Two” frames in AD.There's a misinterpretation that AD cannot use “two” systems to observe a phenomenon, or that it cannot interchange information between “two” systems observing a phenomenon. AD says that in Physics, only a single System of Coordinates or Frame and only ONE Observer is needed. AD says that it is possible to build a Physics in which the Phenomenon is directly observed by any number of observers in relative motion and to interchange information between them. AD also says that we cannot “use two tied” frames (Lorentz’s transform) to observe a phenomenon because this introduces a false physical solution even though the mathematical solution is right. This doesn’t mean that we cannot use two independent (untied) systems to observe a phenomenon. What does this mean, practically speaking?In Lorentz, the constant distance x is introduced in the equation that defines two systems in relative inertial motion, and x is automatically decreased or increased by the Lorentz coefficient g. In Lorentz, Fig 1, x “is tied” to the g relativistic coefficient and is simultaneously “tied” to the System O’ in motion represented by v t.
(Equation (23) (Lorentz increases what is constant and Lorentz and SR are equivalent to applying the Kinetic Energy equation to an object at rest).
x’= g (x + v t) = g x + g v t (23)
In
AD, the constant distance x1 (Fig. 3), which is not related
to any motion in its system or frame is not introduced in the equation
that defines the relative motion between two different positions or
between two Observers, who are not “tied” together through the g
coefficient (Equation (23)). In
AD, x1 “is not tied” to the g relativistic coefficient.
(Equation (24). P, at x1 distance from the origin of O, is
moving together with O in Fig. 3 and O as the inertial frame is moving
with respect to O’. Consequently, the distance x1 is constant
and distance x is the only distance that will change. (Fig.3). It
is impossible to apply the Principle of Relativity to something that
is not in motion, P with respect to O or x1. (AD doesn’t increase what is constant and consequently AD doesn’t apply the Kinetic Energy equation to an object at rest).
Using two systems of coordinates or frames, O and O’, will not change anything under the AD concept. Starting [3] the electromagnetic wave from the origin of frame O’, an observer will measure a distance x at time t equal to x = c t, written in the classic notation as
x2 – c2 t2 = 0 (25)
The wave front will reach P at
distance x’ at time t’ and the equation is
We can write equation (25) and (26) as
x2 – c2 t2 = x’2 – c2 t’2 (27)
The transformation must also be invariant if replacing x’ and t’ by their values as a function of x and t when the velocity of one system with respect to the other is v, giving
0 = 0
Equation (27) is equal to equation (22) and also to the Lorentz equation (5).
Carezani used equation (22) or equation (27) to obtain the AD Relativistic Coefficient equal to g.[4]
Using the traditional notation, we have
x’ = g v t (28)
y’ = y
z’ = z t’ = g t (29)
Equation (28) is equivalent to Lorentz equation (6) and equation (29) to equation (7). From this, it is straightforward to get the AD equations. This creates a Physics, not just a Mathematics. It is Physics because the Principle of Relativity is applied to what is in motion, System O (x) not to what is at rest, P (x1). The Lorentz mistake – which creates only a Mathematics – is to apply the Principle of Relativity to that which has no motion, P (x1).
If
in equation (27) x’ and t’ are
replaced by the values in equation (30) and (31) under the initial condition that v
= c (Electromagnetic wave propagation) the equation (27) is invariant and simultaneously
is valid when c = v without involving any contradiction, as will be
shown in the numerical examples.
Simplifying
The equation's right term equals 0 if v = c, the initial condition: An electromagnetic signal traveling at c with a radial propagation makes the transformation invariant. If v = 0, x is equal zero. This is a physically correct value because v = 0 (See footnote 4) means that the body has no motion and x = 0. What happens if c is different, that is equal v? Evidently if in equation (36) c is taken equal to v, the right side term is also 0.
Numerical
examples. (SR and AD) To show the Lorentz incongruencies,
nothing is clearer than numerical examples. Using exactly the same setting
as in the “Superfluous System:” x = 100 m
t = 10^-7 s v
= 0.8 c c = 3 10^8 m As is shown in equations (18)
and (19), the result are:
x’ = 126. 666 666 666 m (37)
t’ = - 2.777 777 777 10-7
s (38)
Time is negative, which is an
absurdity. Of course, SR believers always invent some ad hoc hypothesis to explain any SR contradiction. In this particular case, it will not work because the ad hoc hypothesis is the Lorentz postulated arm contraction to explain the Michelson-Morley experimental failure to detect the Ether. But the Lorentz contraction concept applies to material objects such as the Interferometer bars used by Michelson-Morley’s experiment. And what is worse, the Lorentz concept creates a dilemma: Length contraction or Ether! If there is length contraction, the Ether exists. The SR supporters don’t believe in the Ether but accept the Lorentz contraction and the Einstein time dilation! No serious physicist can understand how an Inertial System produces the force to provoke the Lorentz contraction on material bars, nor understand how something that doesn’t exist, the force, can contract something immaterial such as length or space. SR applies the concept of length contraction to distance, which is space. But as the Ether doesn’t exist (Aberration) the Lorentz bar contraction or the SR length contraction are both flawed. Nevertheless, even though the concept is erroneous, SR insists on applying it to space as an ad hoc hypothesis to correct the failure in the Lorentz-SR equations to calculate distance and time. Nevertheless, in the present example, if the distance could be corrected, the time will continue to be flawed.
Time continues to be negative,
which make no sense.
SR.
(First case). [5]
v’ = 1.127 272 c (42)
When Frame O, Fig. 2 and 3 [6] passes Frame O’, the respective observers synchronize the clocks, interchanging information. O is telling O’ that he will travel 10-7 second at v = 0.8 c and the distance to Point P is 100 meters. When O’ is an SR Observer he thinks: Observer O is trying to deceive me. He is telling me that his distance to P is 100 m but I know that the length is contracted. He applies the Lorentz contraction measuring 60 m because the Lorentz factor g with v = 0.8 c is equal to 0.6 but he will not apply the value to time equation (13) or (38). He will make a trick applying the value directly to the result (39) and x’’ = 206.666 666 666 – 60 = 146.666 666 666 m.
He will make another trick: He will not apply time dilation to t (10-7 s) and will not introduce the length construction to x in the original equation (39). Dividing
146.666 666 666 by the “normal time” 6.111 111 111 (40) he get v’’ =
240 000 000 m or 0.8 c. The trick is working! Applying the same
concept directly to time dilation with the results in equation (41) we have 6.111 111 111
10-7 / 0.6 = 10.185 185 185 10-7 v’’’ = 146.666 666 666 / 10.185 185 185 10-7 = 144 000 000 m/s = 0.48 c This doesn’t work!
Applying SR’s rules, the failure is evident: v’’’ is not 0.8 c!
The technique is simple: To pass off the contraband of a solution that gives good results, even though it violates the rules of SR.
What happens if SR works with its own concepts and rules?Lorentz’s contraction is 100 * 0.6 = 60 m and
v’’’’ = 1.076 923 c (45)
Without applying any trick, the
velocity of System O is not 0.8 c: It is faster than Light! v’’’’’ = 0.857 142 c (48)
Accomplishing all SR’s rules the velocity is not 0.8 c: It is 0.857 142 c
The failure is total, because the equations were obtained from the initial condition that the electromagnetic wave travels at c, not v’ = 1. 127 272 c or v’’’’ = 1.076 923. In the example, System O is traveling at 0.8 c, not at any other velocity.
AD. (First case).
In units of light velocity:
This is System O traveling at velocity v. AD finds the right solution without any tricks or ad hoc hypotheses.
SR.
(Second case) In this example only the value of the distance is changed.
x = 200 m t = 10-7 s v = 0.8 c m/s c = 3E8 m/s
v’ = 373.333 333 333 / 10.555 555 555 10-7 = 353 684 210 m/s (55)
v’ = 1.178 947 369 c
A velocity larger than c. (56)
Now, employing the contraction trick
x’’ = 200 x 0.6 = 120 m (57)
x’’’ = 373.333 333 333 – 120 = 253.333 333 333 (58)
v’’’ = 253.333 333 333 / 10.555
555 555 10-7 = 240 000 000 m
(59) Taking the Light velocity as the unit
v’’’ = 0.8 c
AD.(Second
case). In AD, nothing changes regarding v and t since v and t have the same values. All that changes is the distance x, now equal to 200 m. As in the AD equations the distance x is not included in the relativistic equation because it is constant in every case when v changes values, the total distance is different but the velocity v is the same.
SR.(Third
case) x = 100 t = 10-6 c = 3E8 v = 0.8
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