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SIMULTANEITY
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any SR/GR hypotheses have been matters of deep discussion. Today, in 1999, we are close to experimentally testing the final GR fantasy: Space dragging (See Chapter 9). But none of these hypotheses was studied so deeply and for so long a time as the SR failure relating to simultaneity. Many recognized physicists worldwide lost a lot of time, in a period spanning 30 to 40 years, trying to explain the problem of simultaneity.
Of course, though SR accepted the Lorentz transformation wholesale with no criticism, the failure lies in the results of this transformation. First at all, we will explain the issue as simply as possible. When one event occurs at point x at time t and another event occurs at point x1 at the same time t, we find, applying SR's equation, that time t' and t'1 differ by an amount equal to
(1)
This circumstance is called the "failure of simultaneity
at-a-distance." Of course, this is an elegant expression to hide
the guilty party: SR. Really,
we hide the guilty party at the outset, because to obtain equation (1)
we use the Lorentz equation, which is the foundation of SR. To tell the complete truth, we need to express the statement as
the "SR failure of simultaneity at-a-distance."
(2)
(3)
(4)
t positive and t negative are eliminated in the equation's
right hand side, and since v is a common factor, we have
(5)
Equation (5) is equivalent to equation
(1) where u = v, and the conclusion is the same. SRs failure of Simultaneity
at-a-distance.
The classical examples given in textbooks,
i.e., a train in motion or two emitters in two parallel systems in relative
motion - introducing time dilation or length contraction - and especially
the example given by Feynman
[1] , are mistaken because the proposition involves
the same error.
Now we will show the mistaken concept
introduced by Feynman, and later we will analyze one of the two others.
Feyman's example describes the synchronization of two clocks inside a
space ship: one in front and the other in the rear. A light signal is
emitted in the middle and the clocks are synchronous because the "distance"
that the light "travels" is the "same." The Observer,
the Astronaut, believes this because he doesn't know that the space ship
is in motion.
This is, evidently, false. He perfectly knows that he is moving with respect
to the origin from where the space ship was launched. If he is actually
"at rest," to stop his motion a force should have been introduced
and this would create a "negative" acceleration that could be
detected by an accelerometer. Also,
it will be shown that he can measure the relative velocity at which the
space ship is actually moving with respect to the origin.
Before the space ship was launched, the
relative two clocks "at rest" are automatically synchronized.
After traveling for a while, the "distance" to the front clock
is longer than the "distance" to the rear clock. (See Fig 2).
They are in motion. When the light emitter emits the light in the space
ship's center, it emits the light at velocity c in all directions and,
precisely at this instant, it is possible to say that the emitter is "at
rest." This is due to the Michelson and Morley discovery.
As the rear clock continues to move in the emitter direction, its arrival time will be shorter and longer for the front clock because it is traveling away from the emitter. (The zero instant when the light was emitted). For an external Observer, the light doesn't arrive simultaneously at the clocks.
This is the Feynman's conclusion, which
is really the SR or Lorentz conclusion.
We mentioned before that the astronaut
knows that he is in motion with respect to his departure's point. Now
we will show that he can know the space ship's velocity if the two clocks
are synchronized. This was done before the launch.
We will also show that the length contraction
hypothesis is totally irrelevant.
Suppose, as normally happens with all
NASA spacecraft that a signal is sent to the space ship. The signal will
arrive first to the rear clock (1) in the space ship and later to the
front clock (2) in Fig 2.
Fig 2 [2] .
Nevertheless it is correct in the explanation to suppose that the Earth is at rest.
As will be proved, this permits us to
calculate at what velocity the space ship is traveling. As the clocks
are synchronized at the launch point, the difference in time gives
the space ship velocity.
We will suppose that the distance between
both clocks is 1000 meters. We know that distance is equal to velocity
times time.
(6)
Why do we use c? Because c is a Universal
velocity, it is constant, and is independent of the Observer and Emitter
velocity. The light velocity is 3 * 10^8 meter/second.
Knowing c and d, we can calculate t.
t is the time that light needs to reach a distance d. This
is equation (6) and from there
(7)
Now the space ship receives a signal
from Earth, Fig 2. Of course, this signal is traveling at c because
it is an electromagnetic signal. This signal enters the rear clock
first, position 1, and later the front clock, position 2, in Fig 2A.
The time difference, i. e. is td = 0.000 003 344 333 second. Applying
the rule of proportionality this time difference represents a distance
(8)
Of course it is the same to say that
the signal traveling at c during 0.000 003 344 333 seconds will travel
a distance equal to
(9)
The time difference represents the time
that the signal travels between the two clocks, 1000 meters, plus
3.3 meters. Consequently the net distance traveled by the space ship
is ds = 3.3 meters.
To see this clearly, it is the same to
get the time difference between the total time td and the
time t related to 1000 meters, multiplying this by the light velocity.
(10)
Fig 3.
When the signal arrives at R, Fig 3D,
the rear clock registers the time. The signal and the space ship continue
in motion and the clocks in Fig 3 move to position E. When the signal
arrives at the front clock F, Fig 3F, this registers the time, giving
a time difference that is equal to td.
The 3.3 meters were traveled in 0.000
003 344 333 second that is the difference between the two clocks.
The space ship velocity is
(11)
Equal to 986.743 Kilometer/second.
If td = 0.000 003 333 773
33 the velocity v = 39.6 Kilometer/second.
The same order of magnitude that the
Earth orbital velocity around the Sun.
If the time difference is td
= 0.000 003 333 3 the space ship is at rest with respect to Earth,
Fig 2B, and if td is smaller than 0.000 003 333 3 the space
ship is traveling in the Earth direction, Fig 2C.
This overwhelmingly shows that the example
for Simultaneity is a fallacy and the example given by Feynman is
totally mistaken.
For an Observer at Earth, according to
Lorentz and SR the distance between the two clocks in the space ship
needs to be shorter, that is, this contraction is a real physical
phenomenon.
To the Observer in the space ship the
two clocks are at rest and repeating the experiment when the two clocks
were at rest in Earth he will find the time difference equal to t
= 000 003 333 3. Simultaneously he could send two signals from each
clock to Earth to control the arrival time difference there. As the
distance between clocks is shorter for the Observer on Earth, he should
detect an arrival time difference shorter than t = 000 003 333 3.
The contradiction is evident between the two Observers, one on Earth
and the other on the space ship.
Regarding this conclusion it is not true that in SR all inertial systems are equivalent or the length contraction is non-existent.
We will discus now the classical experiment
mentioned in many textbooks.
The classical textbook example is the
following [3]

B is in motion with respect to A at 30
000 Km/s.
After
1 s, a pulse of light has spread out from A's lamp a distance 300
000 km and has reached point X. However, after 1 s the light from
B has moved to B' during the second, the light has reached y', which
is 330 000 km from A.
We will show that the fallacy of the
argument is hidden in the common statement: "From A's point of view.......... " (The same reference) To get a "point-of-view", the Observer at
point A needs to receive a signal from X, and if this signal is also
a light beam, the Observer at A will measure a time of 2 seconds in
his clock.
We will suppose for simplicity that the
Observer at B' is now "at rest" after travelling the 30
000 km in a second. From his point of view at B' he will receive a
light beam that will travel 300 000 km from B to Y and 270 000 km
from Y to B'. This means that he will receive the signal in his clock
in 1.9 second at his position at B'.
The calculation is a simple proportion.
If 300 000 km means 1 second, 570 000 km (300 000 + 270 000) is equal
to
t = (570 000 km * 1 s) / 300 000 km = 1.9 s (12)
Everything works perfectly because we
know that the light velocity is a Universal Constant independent of
Observer or Emitter states of motion.
We will show now the Autodynamics solution
regarding "failure of simultaneity at-a-distance."
From the theoretical point of view, AD can prove that simultaneity
is a simple problem related to signal velocity that transmits information
from one point in space to another. From the practical point of view, the solution only involves a simple
calculation, knowing the velocity of the signal that transmits information.
To show the conclusion in the first paragraph
the following is conclusive.
Suppose that a body is traveling at a velocity equal to 0.8 of c and is traveling for 2 seconds
The distance X of the particle from its
point Xo "at rest" is
X = 0.8 c * 2 s = 240 000 km/s * 2 s = 480 000 km (13)
To know this, the Observer in Xo needs
to receive a signal from X, that is to say, the signal needs to travel
another 480 000 km. If the signal travels at light velocity, the time
measured by the Observer at Xo is equal to 3.6 seconds. 2 seconds
of this is the time that the particle traveling at 0.8 c needs to
reach point X and 1.6 s is the time that the signal traveling at c
needs to travel 480 000 km to reach Xo.
If the signal travels at 27 c, the time
t is equal to 2.05925.
2 seconds, as before, is the time that the particle needs
to reach point X and 0.05925 is the time that the signal traveling
from X at 27 c needs to reach point Xo.
480 000 / 27 * 300 000 = 0.05925 s (14)
Of course if v = infinite, the time that
the signal needs to travel from X to reach Xo is equal zero and the
time measured by Observer at Xo is only 2 seconds.
This clearly shows that "relativity"
is given by c but, generalizing, "relativity and simultaneity"
are given by the velocity to what information is transmitted.
Regarding only simultaneity, it is now
clear that if the velocity of information is infinite, all Observers
in the Universe will see simultaneously all phenomena at different
locations happening at the same time.
If the transmission velocity is not infinite, the communication between any Systems in Relative Motion will restore simultaneity only because the transmission velocity is independent of the Observer or Emitter states of motion.
As conclusion, to AD, the failure of simultaneity is only the SR Failure of Simultaneity. For AD there is not any failure and truly the phenomenon simply doesnt exist.
[1] .- "The Feynman lecture on
Physics," Feynman, Leighton and Sands.
Volume I, section 15.6 page 16-7. Fifth Edition 1975, Publisher
Addison-Wesley Publishing Co., California, London, etc.
[2] .- In the example we suppose that
Earth is "at rest" and this is not true. It is "at
rest" for the spacecraft before launch. But, of course, after
launch the spacecraft also possesses the Earth's motion, but later
this also changes direction and velocity in its orbital motion.
The Observer in the space ship needs to know the Earth motion
to subtract or to add vectorial velocity from its own values.
In practice, this is complicated, as happens with real spacecraft,
but through the Doppler Effect, triangulation, etc. the theoretical
explanation is valid because all references could be referred
to the Sun, or more precisely to the Universal System of Coordinates
used by Astronomers. NASA normally uses a system related to a
far away Star that the spacecraft "can see."
[3] .- Franklin Miller, Jr. College Physics Fifth Edition 1982, page 666,
Harcourt Brace Jovanovich, Inc, New York, San Francisco, etc.
This kind of conceptual mistakes are also teaches in Universities.
The Associate Professor of Physics D. P. at University of Virginia
gives the example. See Chapter 4 on Neutrino.
[4]
.- As ADs conclusion the failure
of Simultaneity is only the SRs failure of Simultaneity. For
AD there is not any failure and truly the phenomenon for AD simply
doesnt exist.